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  1. Asked: August 23, 2023In: Civil Engineering

    how to practise

    Amar yadav
    Added an answer on September 24, 2023 at 1:12 pm

    https://youtube.com/playlist?list=PLM-vGSGVntt1-g6SexTMe37G70Z9FmsTQ&si=2Rf4Tj1thdwJk5iU visit this channel to clear your doubt

    visit this channel to clear your doubt

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  2. Asked: August 2, 2023In: Others

    Exam ayo ksari padney ho🥲

    shaswot
    Added an answer on August 19, 2023 at 4:41 pm

    1st sem eh..u will get used to

    1st sem eh..u will get used to

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  3. Asked: April 21, 2023In: Others

    A question or an error I run over just now and the question is to the devs. I’m sorry this might sound rude but no downloaded files are ever in the download section.

    shaswot
    Added an answer on July 21, 2023 at 10:58 pm

    facing same problem :(

    facing same problem 🙁

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  4. Asked: April 29, 2023In: Electronics and Communication

    Instrumentation System ko question paper xa katai?

    shaswot
    Added an answer on July 21, 2023 at 10:56 pm

    ioe syllabus app ma janus sab subejct ko latest ani oldest paper cha

    ioe syllabus app ma janus sab subejct ko latest ani oldest paper cha

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  5. Sorry it is a private answer.

  6. Asked: April 15, 2023In: Electrical

    About back exam

    Aashutosh Jha Beginner
    Added an answer on April 16, 2023 at 5:39 pm

    Yes milxa.. But tyo 2 tai subject same semester ko hunu parxa. For example, yedi timi le 1st sem ko 1ota ra 3rd sem ko 1ota back ko lagi apply gardai xau vane, tmilai 2000 nai pay garnu parne hunxa, but dubai subject 1st sem kai ho, ra 3rd sem kai ho vane 1000 matrai pay garnu parne hunxa

    Yes milxa.. But tyo 2 tai subject same semester ko hunu parxa. For example, yedi timi le 1st sem ko 1ota ra 3rd sem ko 1ota back ko lagi apply gardai xau vane, tmilai 2000 nai pay garnu parne hunxa, but dubai subject 1st sem kai ho, ra 3rd sem kai ho vane 1000 matrai pay garnu parne hunxa

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  7. Asked: March 17, 2023In: Computer Engineering

    Electronics Op-Amp

    shaswot
    Added an answer on April 5, 2023 at 9:59 pm

    compare it with omp amp as adder circuit and suppose anyone one resistor eg. R3=10Kohm then its game on

    compare it with omp amp as adder circuit and suppose anyone one resistor eg. R3=10Kohm then its game on

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  8. Asked: March 13, 2023In: Civil Engineering

    help

    shaswot
    Added an answer on April 5, 2023 at 2:55 pm

    insights ratni

    insights ratni

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  9. Asked: April 5, 2023In: Computer Engineering

    diode numerical

    Aashutosh Jha Beginner
    Added an answer on April 5, 2023 at 12:54 pm

    Using KCL, a) 1 - D1 - (I1 * 1000) = 0 [For ideal diode D1 = 0] or, 1=1000 * I1 So, I1 = 0.001 A = 1mA b) 2- D2 - (I2 * 1000) = 0 [For ideal diode D2 = 0] or, 2 = 1000 * I2 So, I2 = 2mA c) 3 - D3 - (I3 * 1000) = 0 [For ideal diode D3 = 0] or, 3 = 1000 * I3 So, I3 = 3mA Total current through 1kΩ = I1Read more

    Using KCL,

    a) 1 – D1 – (I1 * 1000) = 0 [For ideal diode D1 = 0]
    or, 1=1000 * I1
    So, I1 = 0.001 A = 1mA

    b) 2- D2 – (I2 * 1000) = 0 [For ideal diode D2 = 0]
    or, 2 = 1000 * I2
    So, I2 = 2mA

    c) 3 – D3 – (I3 * 1000) = 0 [For ideal diode D3 = 0]
    or, 3 = 1000 * I3
    So, I3 = 3mA

    Total current through 1kΩ = I1 +I2 + I3
    = 1mA +2mA + 3mA
    = 6mA

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  10. Asked: March 23, 2023In: Computer Engineering

    C++

    Best Answer
    Udhav Pathak
    Added an answer on March 24, 2023 at 12:41 pm
    This answer was edited.

    #include<iostream>#include<cstdlib> #include<fstream> using namespace std; class student { public: char name[20]; int roll; float marks; public: void input( ) { cout<>name; cout<>roll; cout<>marks; } void display( ) { cout<<"\n Name= "<<name<<endRead more

    #include<iostream>#include<cstdlib> #include<fstream> using namespace std; class student { public: char name[20]; int roll; float marks; public: void input( ) { cout<>name; cout<>roll; cout<>marks; } void display( ) { cout<<“\n Name= “<<name<<endl; } }; void writerecords( ) { student s[10]; fstream fout; fout.open(“student.txt”, ios :: out | ios :: app | ios :: binary); cout<<“Enter the info of 10 student for writing into binary file:\n “; for(int i = 0; i<10; i++) { s[ i ].input( ); fout.write((char *)&s[ i ], sizeof(s[ i ])) ; } fout.close( ); } void displayspecificrecord( ) { student s; fstream fin; float highest = 0; fin.open(“student.txt”, ios :: in | ios :: binary); while(fin.read((char *)&s, sizeof(s))) { if(highest < s.marks) highest=s.marks; // here we find out the highest marks among 10 students } fin.close( ); fin.open(“student.txt”, ios :: in | ios :: binary); while(fin.read((char *)&s, sizeof(s))) { if(highest==s.marks) { s.display( ); } } fin.close( ); } int main( ) { int n; while( 1 ) { cout<<“\n 1. Add record: “<<endl; cout<<“2. Display record of student whose mark is highest: “<<endl; cout<<“3. Exit: \n”; cout<>n; switch( n ) { case 1: writerecords( ); break; case 2: displayspecificrecord( ); break; case 3: exit(0); default: cout<<“The choice you entered is wrong: “; } } return 0; }

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